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This is set up as a PowerPoint show so it will not print.  <<5 G"`P p B 0 7Answers   <8  `N  Don t look at the answers until you think about the question!!!!AA   B>6w ,PowerPoint 2002 requiredH  0޽h ? 33, $ ___PPT10 .`&$+Dh ' b= @B D# '  =0BcancelBubble@BA?%<(<*%<(<*_%(D' =%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*D' =%(D' =A@BB#BB0B%(D)' =+4 8?^CBhiddenBCBvisibleB*o3>+B#style.visibility<*+p+0+  ++0+  +b x  0`(  ` ` 00W pZ =How do the following quantities change if the (H+) increases?,>0  @ h 0`  .` #"0`  ` Bd ?`  > @` ` Bm ?   > @`  ` B @`  ` B} ?P  > @`  ` B ?  Lchange @`  ` <Ȏ ff?0` gpOH @`  ` < ff? 0 i(OH-)2  @` ` <L ff?P 0  LpH @` ` < ff?0P  h(H+)2  @` ` < ff?0 Rvariable   @`fB ` 6o ?0`0`B ` 01 ?`fB ` 6o ? ` fB ` 6o ?0 `B ` 01 ?0 `B ` 01 ?P 0P `B ` 01 ? 0 `B ` 01 ?0 fB ` 6o ?`0` `B %` s *ff"`` p g  &` < G"` B 0 7Answers`B '` s *ff"``  B g `B (` s *ff"`` g `B )` s *ff"`` g l *` 6 "`0 l +` 6 "`0 P 0 l ,` 6 "`0  R /` <8 P p *(H+)(OH-) = Kw or pH + pOH = 14 at 25oCl+    ,  l 0` 6 "` PH ` 0޽h ? 33  ___PPT10 .+D ' b= @B Dp '  =0BcancelBubble@BA?%<(<*&`%<(<*&`_%(DD ' =%(DC' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<**`D' =1:Bhidden*o3>+B#style.visibility<**`%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*+`D' =1:Bhidden*o3>+B#style.visibility<*+`%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*,`D' =1:Bhidden*o3>+B#style.visibility<*,`%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*0`D' =1:Bhidden*o3>+B#style.visibility<*0`%(+ b  % Pj(  r  S 8  `}     <4 @t` ; Acetic acid   <  ; Formic acid   <    < Benzoic acid   <(    AHydrochloric acid    < ,$ 0 i5What do you need to look up to address this question?663n8 @  @    <8 @p ` F 1.8 x 10-5     < p  F 1.8 x 10-4     <   F 6.5 x 10-5     <\ `   l0very large  strong acid  RB  s *Do00RB  s *DoppRB  s *Do  RB  s *Do    < G3f"`p  B 0 xHint Ka s& 8      < z  51  <4 @ 52  <|   53  < 0 54  <G"`p B 0 6AnswerH  0޽h ? 33c[___PPT10;.@pX+qD ' b= @B D' = @BA?%,( < +O%,( < +D' b=%(%(D' =%(D8' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =-g6B fade*<3<* D'  =0BcancelBubble@BA?%<(<*%<(<*_%(D' =%(D' =%(D3' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-o6Bdissolve*<3<*D'  =0BcancelBubble@BA?%<(<*%<(<*_%(Dv' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB0-#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*+8+0+  +b  % ~vp(    0@ `  }5What is the cause of the Kb variation for the series?,6   0#P yGHow does the structure differ for the series of compounds listed below?HHx  <A ??P  8 0P  0Pn2  0Ԕ"`0Pn2   0Ԕ"`0Pn2   0Ԕ"` 0 P8 0 0  00lB  <DԔ00   <t*0 [ ,Decreasing electronegativity of central atom--    </G"` B 0 6Answer  <4G"``   B 0 6Answerl  6 "` H  0޽h ? 33___PPT10. +D' b= @B D'  =0BcancelBubble@BA?%<(<* %<(<* _%(D' =%(D' =%(D3' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =-o6Bwipe(up)*<3<* D%'  =0BcancelBubble@BA?%<(<*%<(<*_%(D' =%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*D' =1:Bhidden*o3>+B#style.visibility<*%(+,b  %  s(   x   <A ??   0= tBHow do the strengths vary as the position of the fluorine changes?CC  HBG=H;Ԕ"`p P B Weaker acids  3  H8AG=H;Ԕ"`   DStronger bases  < KG"` B 0 6Answer  B+B#style.visibility<* %(D'  =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D'  =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D'  =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D'  =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* D' =%( D' =A@BBBB0B%(D'  =+4 8?`CB ppt_xBCB1+ppt_w/2B*Y3>B ppt_x<* D '  =+4 8?XCB ppt_yBCB ppt_yB*Y3>B ppt_y<* D' =1:Bhidden*o3>+B#style.visibility<* %( D' =A@BBBB0B%(D'  =+4 8?`CB ppt_xBCB1+ppt_w/2B*Y3>B ppt_x<* D '  =+4 8?XCB ppt_yBCB ppt_yB*Y3>B ppt_y<* D' =1:Bhidden*o3>+B#style.visibility<* %( ++0+  ++0+  ++0+  ++0+  +b   (    <gGff"`P @B 0B 0 3HCNY8 :   00z `  C 0A formic_acid:    <k  5HCOOHG8   00t P  C A HCN   <o . 3HCN  <sGff"`! @B 0B 0 5HCOOH  0v@p {IHow do the two weak acids below differ based on the distribution diagram?JJ  <{G"` B 0 7Answers  <~P p IHCN is weaker than HCOOH.l  6 "`   < P j:Push the acid buttons to return or flip to either diagram.;;H  0޽h ? 33J B ___PPT10" .m+D ' b= @B DW'  =0BcancelBubble@BA?%<(<*%<(<*_%(D+' =%(D' =%(D{' =4@BBB B%()))D' b=1:Bvisible*o3>+B#style.visibility<*%(D' b=-6B+checkerboard(across)*<3<*D%'  =0BcancelBubble@BA?%<(<*%<(<*_%(D' =%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*D' =1:Bhidden*o3>+B#style.visibility<*%(D%'  =0BcancelBubble@BA?%<(<*%<(<*_%(D' =%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*D' =1:Bhidden*o3>+B#style.visibility<*%(+(0b me*9L(  L L < g T$Will the following solutions buffer?%%p  `  7L #""` `  L BL? `  Lno @` L BP?   0.1 M NaCOOH 0.05 M NaOH , @` L B?  Nyes* @`  L BD?    0.1 M HCOOH 0.05 M NaOH @`  L B?`  Myes @`  L B?   0.1 M HNO2 0.05 NaNO2 D     @`  L B@?  Lno @`   L B?   0.1 M HCl 0.1 M NaCl , @` L B?` Lno @` L B?  0.1 M HCOOH 0.1 M NaOH  @` L B?  Myes @` L B?  0.1 M HCOOH 0.1 M NaHCOO @` L <ff?"`` Ubuffer? @` L <ff?"`  Vsolution   @` L B\ ?   F @` L <(ff?  Ubuffer? @` L <1ff?  Vsolution   @`fB L 6o ? ``B L 01 ?  `B L 01 ?  `B L 01 ?  fB L 6o ?  ` fB L 6o ?   `B L 01 ? `B L 01 ?  `B L 01 ?  `B  L 01 ? fB !L 6o ?`` `B "L 01 ? ``B #L 01 ? ``B $L 01 ? ` l 0L 6 "`  l 1L 6 "`p l 2L 6 "`  l 3L 6 "`p l 4L 6 "`l 5L 6 "`  6L <9G"` B 0 7Answers 8L <<p0 b2*can form salt by partial neutralization with base33H L 0޽h ? 33c[___PPT10;. ]+D' b= @B D'  =0BcancelBubble@BA?%<(<*6L%<(<*6L_%(Df' =%(DV' =%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*0LD' b=1:Bhidden*o3>+B#style.visibility<*0L%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*1LD' b=1:Bhidden*o3>+B#style.visibility<*1L%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*2LD' b=1:Bhidden*o3>+B#style.visibility<*2L%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*3LD' b=1:Bhidden*o3>+B#style.visibility<*3L%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*4LD' b=1:Bhidden*o3>+B#style.visibility<*4L%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*5LD' b=1:Bhidden*o3>+B#style.visibility<*5L%(D' =%(DX' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*8L%(D' =-6B+checkerboard(across)*<3<*8L+8+0+8L +kb  %  (    < ]-How do you prepare a buffer with a pH of 4.5?..2  0 & TIdeally find a weak acid with a pKa of 4.5 and prepare a solution where (HA) = (A-).@U" .  2  <_G"` 0 B 0 ? Ideal Answer$  0Tcp  \In reality, acetic acid with a pKa of 4.74 is the closest to the required pH. So what next?*]! ;;  0h   aFor acetic acid, the salt/acid ratio is found from rearranging the Ka and substituting in the pH:*bD `   c $A ??     <hG"`  B 0 > Real Answer  H  0޽h ? 33___PPT10.@k+D' b= @B D'  =0BcancelBubble@BA?%<(<*%<(<*_%(D' =%(D' =%(D@' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-o6Bdissolve*<3<*D{ '  =0BcancelBubble@BA?%<(<* %<(<* _%(DO ' =%(D' =%(D@' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-o6Bdissolve*<3<*D' =%(DV' =A@BB5BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<*D' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<*D' =-g6B fade*<3<*D' =%(pDI' =4@BB5BB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<* D' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<* D' =-g6B fade*<3<* ++0+ ++0+ ++0+ +)b  %   (* (  (p ( H8FQ{TA?p  ( 0""`T ,$@ 0`2 ( s *"`pP f2 ( 0>"`@  ( 0v"` p` ,$@  02 ( s *"`   ,$@ 0) ( 0~ KThe amino acid glycine is amphoteric. Why is it an acid and a base in one? .L6, (  ( <>E,$ 0 N Loss of H+(   ( <>,$D  0 N Gain of H+(   ( <L h H2N-CH2-COOH@     ( < \U,$ 0  H3N+-CH2-COOHV     ( <ԟ U,$ 0 t H2N-CH2-COO-L     ( <p SChime structure,B 0 ( <̫  U%Use the mouse click to see animation.&&H ( 0޽h ? 33___PPT10.g-+KVDu' b= @B D0' = @BA?%,( < +O%,( < +D6 ' b=%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*(%(D#' =4@BB1BB%()?)?Dw' b=.?7 BBBBBQM 3.33333E-6 6.79612E-7 L 0.15 0.09986 *3>*B ppt_xB ppt_y=@0BBAApBB=BL=<*(D/' =%(D@' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =-o6Bdissolve*<3<* (D' =A@BBBB0B%(D' =1:Bhidden*o3>+B#style.visibility<* (%(D' =%( D@' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =-o6Bdissolve*<3<* (D)' b=%(D#' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*(%(D+' =4@BB1BB%()?)?D' b=.G7 BBBBBYM 2.77556E-17 -2.02497E-6 L 0.175 -0.09986 *3>*B ppt_xB ppt_y=@0BBAApBB33=BL<*(D' =4@BBBB%(D' =1:Bhidden*o3>+B#style.visibility<*(%(D' =4@BBBB%(D' =1:Bhidden*o3>+B#style.visibility<*(%(Ds' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*(%(D' =A@BBBB0B%(D' =1:Bhidden*o3>+B#style.visibility<* (%(D' =%(D3' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<* ( %(D' =-o6Bdissolve*<3<* ( D' =%( D@' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* (%(D' =-o6Bdissolve*<3<* (++0+ ( ++0+ ( ++0+ ( ++0+ ( ++0+ ( +p6b-K0  , (  ,p , H8FQ{TA?PpG f , 0""`  , 0v"`` p ,$@ 0 , 0P @The amino acid glycine forms a Zwitterion. How does this happen?.A+, : , s *"`0` ,$D 0 :Transfer of H+ from carboxylic acid group to amine group.H; + , <P  h H2N-CH2-COOH@   + , <\,$ 0  H3N+-CH2-COO-b    `2  , s *"`PP 2  , s *"`0 ` ,$@ 0  , 0p`  ,$  0 7+ 20  , <P$W ,$  0 5-0  , 00 6d ,$  0 DA dipolar ion forms. , 0 0,$  0 k!intramolecular acid-base reaction""f2 , 0>"`p@  , < Z (  , < / B 0 oChime structure.B 0 , 0 p U%Use the mouse click to see animation.&&H , 0޽h ? 33''___PPT10'.g-+v#&D&' b= @B D%' = @BA?%,( < +O%,( < +D' b=%(D ' =%(D' =A@BBBB0B%(D' =1:Bhidden*o3>+B#style.visibility<*,%(D@' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =-o6Bdissolve*<3<*,D' =4@BBBB%())))?D' b=1:Bhidden*o3>+B#style.visibility<* ,%(D' =4@BBBB%())))?D' b=1:Bvisible*o3>+B#style.visibility<* ,%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*,%(D+' =4@BB#BB%()?)?D' b=.G7 BBBBBYM 1.11022E-16 2.8294E-6 L -0.37917 0.01664 *3>*B ppt_xB ppt_y=@0BBAApBB""BBX<<*,D' =%(DX' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =-6B+checkerboard(across)*<3<*,Dn' b=%(D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* ,%(D' =0l9 BBzCzCBB*<3<* ,%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<* ,%())?D' =-g6B fade*<3<* ,D ' =%(DV' =A@BB5BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* ,%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<* ,D' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<* ,D' =-g6B fade*<3<* ,DV' =A@BB5BB0B%(D' =1:Bvisible*o3>+B#style.visibility<* ,%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<* ,D' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<* ,D' =-g6B fade*<3<* ,D}' =%(D%' =A@BB4BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =0l9 BBzCzCBB*<3<*,%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*,%())?D' =-g6B fade*<3<*,++0+, ++0+, ++0+, ++0+ , ++0+ , ++0+ , ++0+, + b  ,(  `  s *"` P P  C (Aglycine` r  6 X??pp  Xx  <A q?? Pp q  0P AWhich species of glycine goes where on the distribution diagram? 0B(2**f2  0>"`  f2  03>"`  f2  0>"` P  < G"`   B 0 7AnswersH  0޽h ? 33___PPT10.B+D' b= @B DT'  =0BcancelBubble@BA?%<(<*%<(<*_%(D(' =%(D' =%(D' =4@BB4BB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*D' =4@BB4BB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =0l9 BBzCzCBB*<3<* %())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<* %())?D' =-g6B fade*<3<* D' =4@BB4BB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =0l9 BBzCzCBB*<3<* %())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<* %())?D' =-g6B fade*<3<* D' =4@BB4BB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =0l9 BBzCzCBB*<3<*%())?D' =.7 BBBBBM -0.46736 0.92887 C -0.37517 0.88508 -0.02552 0.75279 0.0908 0.66613 C 0.20747 0.57948 0.21649 0.50394 0.23177 0.40825 C 0.24705 0.31256 0.22118 0.15964 0.18264 0.09152 C 0.1441 0.02341 0.03802 0.0 0.0 0.0 *3>*B ppt_xB ppt_y=B0B<*%())?D' =-g6B fade*<3<*+/b nf+-P(  Pv p  P# #""PpP  P Bh2?   L>7 @` P B<?   gKCH3COO.  @` P Bl5?`  L<7 @` P BO?p `  eNH4Cl.  @`  P B7?  K7 @`  P Ba?   hNaBr @`  P B`j?`  L>7 @`  P Bht?p`  [NaNO2$  @`  P Bn? L>7 @` P B؆?  gNaF @` P Bn?`  K7 @` P Bx?p` [NaNO3$  @` P <ff?"` PpH @` P <$ff?"`  RSalt @` P B$?   F @` P <ff?`  PpH @` P <ff?p` Rsalt @`fB P 6o ?p`B P 01 ?p `B P 01 ?p `B P 01 ?p fB P 6o ?p  fB P 6o ?pp `B P 01 ?`` `B P 01 ?  `B P 01 ?  `B P 01 ? fB  P 6o ? `B !P 01 ? `B "P 01 ? `B #P 01 ?   $P 0l` D l:What is the pH of the following salts in aqueous solution?;;l %P 6 "`` l &P 6 "`@  l 'P 6 "` P l (P 6 "`@   l )P 6 "` P l *P 6 "`0  +P <XG"` B 0 7AnswersP ,P <T Dweak acid anions, A-, produce OH- weak base cations, BH+, produce H+bE      ,l -P 6 "` PH P 0޽h ? 33___PPT10.`%+D' b= @B D'  =0BcancelBubble@BA?%<(<*+P%<(<*+P_%(DW' =%(DV' =%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<**PD' b=1:Bhidden*o3>+B#style.visibility<**P%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*)PD' b=1:Bhidden*o3>+B#style.visibility<*)P%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*(PD' b=1:Bhidden*o3>+B#style.visibility<*(P%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*'PD' b=1:Bhidden*o3>+B#style.visibility<*'P%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*%PD' b=1:Bhidden*o3>+B#style.visibility<*%P%(Dy' =4@BBB B%()))D' b=-6B+checkerboard(across)*<3<*&PD' b=1:Bhidden*o3>+B#style.visibility<*&P%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*-PD' =1:Bhidden*o3>+B#style.visibility<*-P%(+b    TT (  T T 0P CRank the following 0.10 M solutions in order of increasing acidity.,D0 T < QHCl3 T <D  RNaCl3 T < 0 RNaCN3  T <00 WNH4Cl6333  T <PR 0 YCH3COOH6333  T <H  7KOH3I  T 0  ;HCl > CH3COOH > NH4Cl > NaCl > NaCN > KOHT<  #6  T <|   T______ > ______ > ______ > ______ > ______ > ______ most acid least acidUUl T 6 "` 0 T <G"` B 0 6AnswerH T 0޽h ? 33___PPT10.`j+Dj' b= @B D%'  =0BcancelBubble@BA?%<(<*T%<(<*T_%(D' =%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*TD' =1:Bhidden*o3>+B#style.visibility<*T%(+D b .&pH(  Hx H <A  ??"p    H 0|"P k9Why does the pH of a sodium cyanide decrease on dilution?:: H 0|'  OOn dilution, less and less hydroxide ion is produced by hydrolysis of the salt.PPl H 6 "` 0P  H <L,G"` B 0 6AnswerH H 0޽h ? 33___PPT10.+Dj' b= @B D%'  =0BcancelBubble@BA?%<(<*H%<(<*H_%(D' =%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*HD' =1:Bhidden*o3>+B#style.visibility<*H%(+q.b /R$^(  $x $ <3 f ~Shifting the aqueous equilibrium heat + HCN CN- + H+r@!  3 3 3 3 3p p  Q$ #""p  $ BC?   B @` $ B+B#style.visibility<*G$%(D' =%(D)' =4@BB BB%(D' =-g6B fade*<3<*I$D' =1:Bhidden*o3>+B#style.visibility<*I$%(D' =%(D)' =4@BB BB%(D' =-g6B fade*<3<*H$D' =1:Bhidden*o3>+B#style.visibility<*H$%(D' =%(pD)' =4@BB BB%(D' =-g6B fade*<3<*J$D' =1:Bhidden*o3>+B#style.visibility<*J$%(D' =%(@D)' =4@BB BB%(D' =-g6B fade*<3<*O$D' =1:Bhidden*o3>+B#style.visibility<*O$%(D' =%('D)' =4@BB BB%(D' =-g6B fade*<3<*P$D' =1:Bhidden*o3>+B#style.visibility<*P$%(+ b  Xu(  XP X C (ASA_TITRp P X C (AWA_TITR @  X <`` `G  a X <t*  b X <` G  a  X <:F ! c  X 0 t p>Identify the substance being titrated in the titration curves.??+  X <  Wa- strong acid 0.10 M, pH = 1 b- strong acid 0.001 M, pH =3 c- weak acid 0.10 M, pKa =6*XS Ql  X 6 "`@ `0` X <  w b X <T ~  a X <G"` B 0 6AnswerH X 0޽h ? 33___PPT10.`D+Dj' b= @B D%'  =0BcancelBubble@BA?%<(<*X%<(<*X_%(D' =%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<* XD' =1:Bhidden*o3>+B#style.visibility<* X%(+b J B \ (  \X \ C 0A ACETIC_ACIDP R2 \ s *0 R2 \ s *` R2 \ s * PP R2 \ s * @ R2  \ s *@ 0   \ <* V  a  \ <$  b  \ <"J  1  c  \ <&zf / a d \ <)z& a e \ 0+` aFor acetic acid being titrated with NaOH, what is the solution composition at each labeled point?bb$: \ <0@ P`  ;HA only3 \ <3P  ? (HA) = (A-) 3 \ <8 v -  YA- > HA6333 \ B>c`  YA- only6333 \ <$<0: P } A- + NaOH6 333Z \ c $"` P Z \ c $"`0 Z \ c $"`P0 Z \ c $"`0` Z \ c $"`   \ <JG"` B 0 7AnswersH \ 0޽h ? 33 ___PPT10 . +D ' b= @B Di '  =0BcancelBubble@BA?%<(<*\%<(<*\_%(D= ' =%(D ' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*\D' =1:Bhidden*o3>+B#style.visibility<*\%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*\D' =1:Bhidden*o3>+B#style.visibility<*\%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*\D' =1:Bhidden*o3>+B#style.visibility<*\%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*\D' =1:Bhidden*o3>+B#style.visibility<*\%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*\D' =1:Bhidden*o3>+B#style.visibility<*\%(+. b `h4(  hx h c $T     h0  `A ? ?"6@ NNN?N0A   h Tfd?"6@ `NNN?N P@,$@ 0 h Tfd?"6@ `NNN?N0`P,$@ 0  h T3fd?"6@ `NNN?N@ ,$@ 0'  h H8X ?"6@ NNN?N`P4,$ 0 =1  3  h <\ ?"6@ NNN?N ,$ 0 =3  3'  h H_ ?"6@ NNN?N@b,$ 0 =2  3;  h Bl]f?"6@ NNN?NP# ,$D  0 WWhich indicator would work?  F pP  h  @ h Nd?"6@ NNN?NpP B h 6D?"0@NNN?Np h Hlh ?"6@ NNN?N ? hpKIn.  ? h Hm ?"6@ NNN?NppW pKIn- 1L   ? h Hs ?"6@ NNN?Np pKIn+ 1L    h <y ?"6@ NNN?N@ Lcolor change range fB h <Do?"0@NNN?NP h H{ ?"6@ NNN?N0 w =x   h H, ?"6@ NNN?N  =x   h <G"` B 0 6AnswerH h 0޽h ? Lx[he2___PPT10.m+a܍]D[' b= @B D' = @BA?%,( < +O%,( < +D' b=%(%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*h%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* h%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*h%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* h%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* h%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* h%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* h%(D' =+4 8?RCBBCB#ppt_wB*Y3>B ppt_w<* hD' =+4 8?RCBBCB#ppt_hB*Y3>B ppt_h<* hD' =+K4 8?CBB#ppt_x+(cos(-2*pi*(1-$))*-#ppt_x-sin(-2*pi*(1-$))*(1-#ppt_y))*(1-$)CB?B*Y3>B ppt_x<* hD' =+K4 8?CBB#ppt_y+(sin(-2*pi*(1-$))*-#ppt_x+cos(-2*pi*(1-$))*(1-#ppt_y))*(1-$)CB?B*Y3>B ppt_y<* hDA'  =0BcancelBubble@BA?%<(<*h%<(<*h_%(D' =%(D' =%(D3' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<*h%(D' =-o6Bdissolve*<3<*hD' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*h%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*h%(+P+0+ h ++0+ h ++0+ h ++0+ h ++0+h ++0+h +-b ~-Kx(  xp  Kx #"" x B?I  ^Neither litmus changed @` x B?P I  ^Red litmus turned blue @` x B? I P  ^Blue litmus turned red @` x Bܾ?I  ^Blue litmus turned red @` x BL?I  ^Blue litmus turned red @` x B? I  dpH constant with water added @` x B?P  I  epH decreased with water added @` x B4?  P I  epH increased with water added @` x Bt? I  dpH constant with water added @` x BT? I  epH increased with water added @` x B ?  YHighly conductive @`  x B ?P   YHighly conductive @`  x B@ ? P   [Slightly conductive @`  x B ?   YHighly conductive @`  x B, ?  YHighly conductive @`  x <p5 ff? jNaCl @` x <7 ff?P  rNaCH3COO8  @` x <J ff? P  qCH3COOH8 @`  x <V ff?  CH3COOH/ NaCH3COOV  @` x <` ff? iHCl @`fB x 6o ?`B x 01 ?`B x 01 ?  `B x 01 ?I I fB x 6o ?fB x 6o ?`B x 01 ?`B  x 01 ?  `B !x 01 ?P P `B "x 01 ?fB #x 6o ? 4x BTd  MCH3COOH*  5x <4j 0 MHCl 6x < n z  mCH3COOH/ NaCH3COO@    7x BLu  * NNaCH3COO*   8x <{  NNaCl Dx <~ ` e5Which solution matches the observations in the table?66l Ex 6 "`pPl Fx 6 "`pPl Gx 6 "`p` Pl Hx 6 "`p @Pl Ix 6 "`p`P Jx <x G"` B 0 7AnswersH x 0޽h ? 33 ___PPT10 .`y+D ' b= @B Di '  =0BcancelBubble@BA?%<(<*Jx%<(<*Jx_%(D= ' =%(D ' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*IxD' =1:Bhidden*o3>+B#style.visibility<*Ix%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*HxD' =1:Bhidden*o3>+B#style.visibility<*Hx%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*ExD' =1:Bhidden*o3>+B#style.visibility<*Ex%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*GxD' =1:Bhidden*o3>+B#style.visibility<*Gx%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*FxD' =1:Bhidden*o3>+B#style.visibility<*Fx%(+ b x|(  |x | <A ??0I   | <  g U%Why does the pH of neutrality change?&&: | 0Y   ZAs temperature increases, Kw increases; hence (H+) increases, which causes pH to decrease.B[  *?l | 6 "` pP | <8 G"` B 0 7AnswersH | 0޽h ? 33___PPT10.+Dj' b= @B D%'  =0BcancelBubble@BA?%<(<*|%<(<*|_%(D' =%(D' =%(DI' =4@BBB B%(D' =-6B+checkerboard(across)*<3<*|D' =1:Bhidden*o3>+B#style.visibility<*|%(+  0 P@(  @X @ C <    @ S  < 0    H @ 0޽h ? 3380___PPT10. $xYklTE>- (RB E婉(J7/HՄh"&Ĩ?@5AA "OSm4 `)zny4a6Ι̹Soo8= C[Z p8"Q:ULhQ2*SY0*Σ?K:ӖDKG_ҙ_K]p.>{BSnoH;|0dAҿ`<:j>|? 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